এখানে নবম দশম শ্রেনির গনিত এর প্রয়োজনীয় সক সুত্র দেওয়া হলেঃ-
- (a+b)²= a²+2ab+b²
- (a+b)²= (a-b)²+4ab
- (a-b)²= a²-2ab+b²
- (a-b)²= (a+b)²-4ab
- a² + b²= (a+b)²-2ab
- a² + b²= (a-b)²+2ab
- a²-b²= (a +b)(a -b)
- 2(a²+b²)= (a+b)²+(a-b)²
- 4ab = (a+b)²-(a-b)²
- ab = {(a+b)/2}²-{(a-b)/2}²
- (a+b+c)² = a²+b²+c²+2(ab+bc+ca)
- (a+b)³ = a³+3a²b+3ab²+b³
- (a+b)³ = a³+b³+3ab(a+b)
- a-b)³= a³-3a²b+3ab²-b³
- (a-b)³= a³-b³-3ab(a-b)
- a³+b³= (a+b) (a²-ab+b²)
- a³+b³= (a+b)³-3ab(a+b)
- a³-b³ = (a-b) (a²+ab+b²)
- a³-b³ = (a-b)³+3ab(a-b)
- (a² + b² + c²) = (a + b + c)² – 2(ab + bc + ca)
- 2 (ab + bc + ca) = (a + b + c)² – (a² + b² + c²)
- (a + b + c)³ = a³ + b³ + c³ + 3 (a + b) (b + c) (c + a)
- a³ + b³ + c³ – 3abc =(a+b+c)(a² + b²+ c²–ab–bc– ca)
- a3 + b3 + c3 – 3abc =½ (a+b+c) { (a–b)²+(b–c)²+(c–a)²}
- (x + a) (x + b) = x² + (a + b) x + ab
- (x + a) (x – b) = x² + (a – b) x – ab
- (x – a) (x + b) = x² + (b – a) x – ab
- (x – a) (x – b) = x² – (a + b) x + ab
- (x+p) (x+q) (x+r) = x³ + (p+q+r) x² + (pq+qr+rp) x +pqr
- bc (b-c) + ca (c- a) + ab (a – b) = – (b – c) (c- a) (a – b)
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